Respuesta :

mickymike92

Based on the data provided, the mass of water produced is 1.26 × 10^-2 g.

What mass of water is produced from the complete combustion of 6. 30×10−3 g of methane?

The equation of the combo of methane is add follows:

CH4 + 2O2 ----> CO2 + 2H2O

  • I mole of methane produces 2 moles of water
  • molar mass of methane = 18 g/mol

moles of methane in 6.30 × 10^-3 g = 6.30 × 10^-3 g/ 18 g/mol

moles of methane = 3.5 × 10^-4 moles

3.5 × 10^-4 moles of methane will produce 2 × 3.5 × 10^-4 moles of water = 7.0 × 10^-4 moles

  • molar mass of water = 18 g/mol

mass of water produced = 18 g/mol × 3.5 × 10^-4 mol = 1.26 × 10^-2 g.

Therefore, the mass of water produced is 1.26 × 10^-2 g.

Learn more about molar mass at: https://brainly.com/question/15476873

Otras preguntas