Answer:
[tex] \boxed{ \tt{j} = \boxed{\tt 13.5}}[/tex]
Step-by-step explanation:
Given equation:
[tex] \sf \cfrac{j}{ \tt3} = \tt 4.5[/tex]
To find:
Value of x
Solution:
[tex] \implies\sf \cfrac{j}{ \tt3} = \tt 4.5[/tex]
Multiply both sides by 3:
[tex]\sf \implies \cfrac{j}{3} \times 3 = 4.5 \times3[/tex]
Use cancellation method to cancel LHS :
[tex] \sf \implies \cfrac{j}{ \cancel3 \: {}^{1} } \times \cancel3 \: {}^{1} = 4.5 \times 3 \: \: [/tex]
[tex]\sf \implies{j} \times 1 = 4.5 \times 3[/tex]
[tex]\sf \implies{j} = 4.5 \times 3[/tex]
Now Multiply the RHS(4.5 and 3):
[tex] \sf \implies{j} = \boxed{13.5}[/tex]
We're done!
Hence , the value of j would be 13.5 .
[tex] \rule{225pt}{2pt}[/tex]
I hope this helps!
Let me know if you have any questions.
