Respuesta :

Answer:

25 J

Explanation:

m = 2 kg

v = 5 m/s

[tex]K.E_{snowball} = \frac{1}{2} m {v}^{2} \\ \\ = \frac{1}{2} \times 2 \times {(5)}^{2} \\ \\ = 25 \: Joule[/tex]