Answer:
[tex]\huge\boxed{\sf 144 + 18\pi}[/tex]
Step-by-step explanation:
If radius = 6, then diameter will be:
d = 2r = 2(6) = 12
So, BC = CD = AD = AB = 12 (Since ABCD is a square)
Area of square:
= length × length
= 12 × 12
= 144
Now,
Area of semi-circle:
[tex]\displaystyle \frac{\pi r^2}{2} \\\\Where \ r = 6\\\\= \frac{\pi (6)^2}{2} \\\\= \frac{\pi (36)}{2} \\\\= 18\pi[/tex]
So, the combined area is:
= Area of square + area of semi-circle
= 144 + 18π
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
