Respuesta :
Explanation:
1L is 1.3 g so 600L is 780 g
1kg= 1000g so
780 g = 0.78kg
I GUESS
Mass in kilograms of liquid air required = 0.78 kg
Given that
1 Litre of liquid air contains 1.3 grams of oxygen ( air )
Determine the amount of liquid air in Kg
volume of air given = 600 L
mass of liquid air required = x
1 litre = 1.3 grams
600 L = x
∴ x ( mass of liquid air ) = 1.3 * 600
= 780 g = 0.78 kg
Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg
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