Answer:
Step-by-step explanation:
x²+y²-2x-10y+1=0
compare with x²+y²+2gx+2fy+c=0
center is (-g,-f)
radius=√(g²+f²-c)
2g=-2
g=-1
2f=-10
f=-5
radius=(1,5)
c=1
let eq. of circle be x²+y²-2x-10y+c=0
∵ it passes through (2,-3)
2²+(-3)²-2(2)-10(-3)+c=0
4+9-4+30+c=0
c=-39
eq. of circle is is x²+y²-2x-10y-39=0
