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Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?.

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The value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

According to the principle of conservation of linear momentum, the total momentum before and after collision is conversed.

[tex]m_av_a_1 + m_bv_b_1 = v(m_a + m_b)[/tex]

where;

  • [tex]v_a_1 \ \ and \ \ v_b_1[/tex] are the initial velocity of the cars before collision
  • v is the final velocity of the cars after collision

since the train car A is at rest, [tex]v_a _1 = 0[/tex]

[tex]m_bv_b_1 = v(m_a + m_b)[/tex]

The relationship between the final velocity and initial velocity of the cars is given as;

[tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex]

Thus, the value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

Learn more about conservation of linear momentum here: https://brainly.com/question/22698801

Answer: the answer is the third option. Edge 2021

Explanation: i just answered the problem

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