Answer:
factorise it
Step-by-step explanation:
in the method ax2 + bx + c
so it can be done just in y
find a common factor
well there isn't one but we can see that we need to factorise it
+1 y2 times 6= 6
because there is only 1 y and you times it by 6
you'll see why when we factorise this
so x the squared number (1) x 6 =6
and the middle number is 5
find two numbers that
x multiply to make six
and add+ to make -5
those numbers are
-3
-2
because -2 + -3 = -5 and -2 x -3 = positive 6
so our answer of y2 + 5y + 6
is identical to = y2 -3y -2y +6
factorise in half
y2 -3y -2y +6
so now we can factorise!
in this bracket we have
a common factor of y in this bracket we have common
factor of 2
= y (y -3) + = -2(y-3)
BUT THERE IS STILL ONE MORE
THEN WE CAN SEE A COMMON FACTOR OF Y-3
put the (y-3) in front and the (-y-2) is left
put y from first bracket and -2 from second bracket into a seperate bracket
yay! factorised
BUT THERE IS STILL ONE MORE
ANSWER = (Y-2) (Y-3)
you can use the rainbow multiplying out of bracket method to prove it works.
PLZ GIVE BRAINLIEST
how it would be written out:
y2 + 5y + 6
y2 -3y -2y +6
y2 -3y -2y +6
y (y -3) -2(y-3)
(Y-2) (Y-3)
