Answer:
[tex]x=\frac{y-3}{2y-3}[/tex]
Step-by-step explanation:
[tex]y=2+\frac{1+x}{1-2x}[/tex]
First, subtract 2 from both sides:
[tex]y-2=\frac{1+x}{1-2x}[/tex]
Multiply both sides by (1 - 2x):
[tex]y-2(1-2x)=1+x\\y-2xy-2+4x=1+x[/tex]
Subtract 1, subtract x, and add 2xy to both sides:
[tex]y-3+3x=2xy[/tex]
Subtract 3x from both sides:
[tex]y-3=2xy-3x[/tex]
Factor out the x:
[tex]y-3=x(2y-3)[/tex]
Finally, divide both sides by (2y-3):
[tex]x=\frac{y-3}{2y-3}[/tex]
Keep in mind that this is undefined at y=1.5. The original equation is also undefined at 0.5.
