Respuesta :

mhanifa

Answer:

  • See below

Step-by-step explanation:

The given diagram doesn't give enough details to state the quadrilateral is a square.

We see all sides are of same length of 9 units. This could be a rhombus too.

In order this quadrilateral is a square all interior angles should be marked as right angles.

Let's assume the above condition is met.

Find the length of both diagonals:

  • [tex]AC=\sqrt{9^2+9^2} =9\sqrt{2} \\BD=\sqrt{9^2+9^2} =9\sqrt{2}[/tex]

Since both diagonals have same length, the quadrilateral is a square.

Break into two parts

  • ∆ABC and ∆ADC

In∆ABC

[tex]\\ \sf\longmapsto AC^2=9^2+9^2=81+81=162\implies AC=9√2[/tex]

In ∆ADC

[tex]\\ \sf\longmapsto AC^2=9^2+9^2=81+81=162\implies AC=9√2[/tex]

  • <D=<B=90°

ABCD is a square.

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