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A circuit is constructed with a 20.0-V power supply and two resistors in series: R1 = 4.00 ohms, and R2 = 2.00 ohms. What is the resulting current in the circuit?

A) 3.33 A

B) 27.0 A

C) 15.0 A

D) 120.0 A

Respuesta :

dragon1524

Answer:

3.33A

Explanation:

total resistors in series circuit (4.0+2.0) = 6.0

following ohms law. V = IR, then I = V/R; but the supply voltage given equals =20,

therefore, 20/6 = 3.33A,

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