Which table of values satisfies the linear equation y=−5/6x−3

x y
−12 7
0 0
12 −13

x y
−6 −8
0 −3
6 2

x y
−12 −13
0 0
12 7

x y
−6 2
0 −3
6 −8

Respuesta :

Answer:

The last answer choice.

Step-by-step explanation:

Check. Plug in the given number for x, and if the given number for y is the answer, then it is correct:

[tex]\left[\begin{array}{cc}x&y\\-6&2\\0&-3\\6&-8\end{array}\right][/tex]

[tex]y = -\frac{5}{6}x - 3[/tex]

When: [tex]x = -6 , y = 2[/tex]

[tex]2 = (-\frac{5}{-6} * -6) - 3 \\2 = (5) -3\\2 = 2[/tex](True)

When: [tex]x = 0 , y = -3[/tex]

[tex]-3 = -\frac{5}{6}(0) -3\\-3 = 0 - 3\\-3 = -3[/tex]      (True)

When: [tex]x = 6 , y = -8[/tex]

[tex]-8 = -\frac{5}{6}(6) - 3\\-8 = -5 - 3\\-8 = -8[/tex](True).

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