Respuesta :
~quadratic equation
======================
2x² + 3x - 20 = 0
= a + b = 3
= ab = 2(-20) = -40
= a = -5
= b = 8
= (2x² - 5x) + (8x - 20)
= x(2x - 5) + 4(2x - 5)
= (2x - 5) (x + 4)
= Solution 1 : x = 5/2 ✔️
Solution 2 : x = -4 ✔️
~ nice to help you ^^
[tex]2x^2 +3x -20 =0\\\\\\\implies x = \dfrac{-3 \pm \sqrt{(-3)^2 - 4 \cdot 2 \cdot (-20)}}{2 \cdot 2}\\\\\\\implies x = \dfrac{-3 \pm \sqrt{169}}{4}\\\\\\\implies x = \dfrac{-3\pm 13} 4 \\\\\\\text{Hence} \\\\x = \dfrac{-3+ 13}{4} = \dfrac{10} 4 = \dfrac{5}2\\\\\text{Or}\\\\x= \dfrac{-3-13}4 = -\dfrac{16}4 =-4[/tex]