Respuesta :

[tex]\dfrac{(2 x^{-3} y^{-2})^5}{(6x^{-1} y^{-8})^2}\\\\\\=\dfrac{32x^{-15} y^{-10}}{36 x^{-2} y^{-16}}\\\\\\=\dfrac{8}{9} \left(\dfrac{x^{-15}}{x^{-2}} \right) \left(\dfrac{y^{-10}}{y^{-16}} \right)\\\\\\=\dfrac 89 \left(x^{-15+2} \right) \left(y^{-10 +16} \right)\\\\\\=\dfrac 89 \cdot x^{-13} \cdot y^6\\\\\\=\dfrac{8y^6}{9x^{13}}[/tex]