Step-by-step explanation:
Given equation is [{(2-2x)/4} = {(4x+12)/3]
On applying cross multiplication then
Since, (a/b) = (c/d)
⇛ab = bc
Where, a = (2-2x), b = (4), c = (4x+12) and d = (3).
Now,
⇛3(2-2x) = 4(4x+12)
Multiply the number outside the bracket with numbers and variables in the bracket.
⇛6 - 6x = 16x + 48
Shift the variable value on LHS and constant on RHS.
⇛-6x - 16x = 48-6
Subtract the values on LHS and RHS.
⇛-22x = 42
Shift the value (-22) from LHS to RHS.
⇛x = 42/-22
Write the obtained answer in lowest form by cancelling method.
⇛x = (42÷2)/(-22÷2)
Therefore, x = 21/-11 = -(21/11)
Answer: Hence the value of x for the given problem is -21/11.
VERIFICATION:
If x = -21/11 then the equation is
[{(2-2x)/4} = {(4x+12)/3]
Substitute the value x = -21/11 in expression, then
⇛[{2-2(-21/11)}/4 = {4(-21/11)+12}/3]
Multiply (-2) from (-21) to get 42 on LHS.
⇛[{2(42/11)}/4 = {4(-21/11)+12}/3]
Again multiply 4 from (-21) to get 81 on RHS.
⇛[{2(42/11)}/4 = {(-81/11) + 12}/3]
Take the LCM of the denominator 1 and 11 is 11 on LHS
⇛[{(2*11 + 42*1)/11}/4 = {(-81*1 + 12*11)/11}/3]
Multiply the numerator on both LHS and RHS.
⇛[{(22+42)/11}/4 = {(-81 + 132)/11}/3]
Add the numerator numbers on both LHS and RHS
⇛[{(64/11)}/4 = [{(48/11)}/3]
Now, conver the division fraction in multiply fraction on both LHS and RHS.
⇛[{(64/11) * 4} = {(48/11) * 3}]
Now, write the numbers in Lower form by cancelling method, on both LHS and RHS.
⇛(16/11) = (16/11)
LHS = RHS
Please let me know if you have any other questions.
