[tex]A = P(1 + \frac{r}{n} )^{nt}\\A = 100(1 + \frac{.12}{12} )^{12(10)}\\\A = 100(1 + .01)^{120}\\\A =330.04\\[/tex]
Therefore the account will have $330.04 (Rounded to the nearest cent) in 10 years at 12% interest compounded monthly.
I hope I've helped! :)
