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henry deposited $2.75 in nickels, dimes, and quarters in his piggy bank. the number of dimes exceeded the number of quarters by 4, and the number of quarters was 7 less than the number of nickels. find the number of nickels dime and quarters he deposited

Respuesta :

The numbers of quarters, dimes and nickels that were deposited are 5, 9 and 12 respectively.

He deposited $2.75 in nickels , dimes and quarter in his piggy bank.

let

number of quarter = x

number of dimes  = x + 4

number of nickels = x + 7

1 dimes = $0.1

1 nickels = $0.05

1 quarter = $0.25

The total money he had in dollars is $2.75. Therefore,

  • 2.75 = 0.25x + (x + 4)0.1 + 0.05(x + 7)

Therefore,

2.75 = 0.25x + 0.1x + 0.4 + 0.05x + 0.35

2.75 - 0.4 - 0.35 = 0.25x + 0.1x + 0.05x

2 = 0.4x

x = 2 / 4

x = 5

Therefore,

number of quarters = 5

number of dimes = 5 + 4 = 9

number of quarters = 5 + 7 = 12

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