Using the Central Limit Theorem, it is found that:
The Central Limit Theorem states that for a sample of size n in a population with standard deviation [tex]\sigma[/tex], the standard error is given by:
[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
In this problem, the standard deviation is [tex]\sigma = 4.298[/tex]
Then, for Data Set 1, [tex]n = 10[/tex], and:
[tex]s = \frac{4.298}{\sqrt{10}} = 1.36[/tex]
For Data Set 2, [tex]n = 20[/tex], and:
[tex]s = \frac{4.298}{\sqrt{20}} = 0.96[/tex]
For Data Set 3, [tex]n = 50[/tex], and:
[tex]s = \frac{4.298}{\sqrt{50}} = 0.61[/tex]
A similar problem is given at https://brainly.com/question/24188986