Answer:
not factorable
Step-by-step explanation:
[tex]x^{2} - 9x +10\\[/tex]
The easiest way to factor is to find two numbers of the "a" value (the coefficient before [tex]x^{2}[/tex]) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:
1 -10 --> 1(-10) gives you -10
1 -1 --> 1(-1) gives you -1
adding these together -10 + (-1) = -11 which does not equal -9.
You could stop here and conclude that this is not factorable by inspection.
Another method: using the quadratic formula to find its roots.
Roots: [tex](\frac{9-\sqrt{41} }{2}, 0)[/tex] and [tex](\frac{9+\sqrt{41}}{2}, 0)[/tex]
