A line contains points (9,-30) and (-1,-42) which equation represents the line that is perpendicular to the given line and passes through point (3,-12)?

Answer: 2) y=-5x+3
Step-by-step explanation:
Calculate the slope of the first line from the two point (9,-30) and (-1,-32). Slope = Rise(y)/T=Run(x)
The Rise is (-30-(-32))=2
The Rise is (9-(-1) = 10
The slope is (2/10) or 0.20
A perpendicular line will have a slope that is the negative inverse of the reference line. The negative inverse of (2/10) is -(10/2) or -5. The new line will have the form y = -5x + b
Find b by using the given point (3,-12) in the equation and solve for b:
y = -5x + b
-12 = -5*(3) + b
b = 3
The equation of the line perpendicular to the line that goes through points (9,-30) and (-1,-32) is
y = -5x + 3