Respuesta :
The final temperature of the water is 106.0 °C
From the question,
We are to determine the final temperature of water.
From the formula
Q =mcΔT
Where Q is the quantity of heat
m is the mass of substance
c is the specific heat capacity of substance
and ΔT is the change in temperature
Also,
ΔT = T₂ - T₁
Where T₂ is the final temperature
and T₁ is the initial temperature
Then, the formula can be written as
Q =mc(T₂ - T₁)
From the question
Q = 7500 J
m = 250 g
T₁ = 98.8 °C
Putting the parameters into the formula, we get
7500 = 250 × 4.184 (T₂ - 98.8)
(NOTE: specific heat capacity of water, c,= 4.184 J/g °C)
7500 = 1046 (T₂ - 98.8)
7500 = 1046T₂ - 103344.8
Then,
1046T₂ = 7500 + 103344.8
1046T₂ = 110844.8
∴ T₂ = 110844.8 ÷ 1046
T₂ = 105.9701 °C
T₂ ≅ 106.0 °C
Hence, the final temperature of the water is 106.0 °C.
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