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How many grams of nitric acid, HNO3, can be prepared from the reaction of 138g of NO2 with 54.0 g H2O according to the equation below:

3NO2 + H2O = 2HNO3 + NO

Respuesta :

Answer:

126 grams

Explanation:

You must convert NO2 and H2O to HNO3 in separate equations to find the limiting and excess reactant.

NO2:

(138g NO2) x (1mol NO2/ 46.01g NO2) x (2mol HNO3/ 3mol NO2) x (63.018g HNO3/ 1mol HNO3) = 126g HNO3

H2O:

(54gH2O) x (1mol H2O/ 18.016g H2O) x (2mol HNO3/ 1mol H2O) x (63.018g HNO3/ 1mol HNO3) = 378g HNO3

Since the NO2 gives the smaller amount of HNO3 its the limiting reactant.

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