Answer:
[tex]10t(t-6)^2[/tex]
Step-by-step explanation:
By looking at the equation
[tex]360 t+ 10 t^ 3- 120t^2[/tex]
we can rearrange it from highest order to lowest:
[tex]10 t^ 3- 120t^2 +360 t[/tex]
Now, what variable is present in all the numbers? "t" is
And what number are all the numbers divisible by? 10.
So then we can factor out a 10t from all numbers:
[tex]10t(t^2-12t+36)[/tex]
Now we can factor the expression inside the brackets separately:
[tex]1*1=1\\(-6)*(-6)=36[/tex]
cross these numbers to get -6 and -6, then when you add, you get -12 which is the b value.
[tex]10t [(t-6)(t-6)][/tex]
Since they're both the same:
[tex]10t(t-6)^2[/tex]
:) hope this helped!
