Answer: E = 26.4 × 10⁻²⁷ j
Explanation:
Given data:
Frequency of photon = 4×10⁷ Hz
Energy of photon = ?
Planck's constant = 6.6 × 10⁻³⁴ js
Solution:
Formula:
E = h × v
v = frequency
Now we will put the values in formula.
E = 6.6 × 10⁻³⁴ js × 4×10⁷ Hz
Hz = s⁻¹
E = 26.4 × 10⁻²⁷ j
The energy of photon is 26.4 × 10⁻²⁷ j.
