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How far does the first car will drive in the 2 hours head start it gets? Now, at t = 2 hours, both cars are moving. How much faster is the second car than the first car? You can determine this by dividing the head start by the difference in the two speeds. If car 1 has a 20-mile head start, and car two is five mph faster, then it will take 20/5 = 4 hours to catch up.

Respuesta :

let they meet after second car travels for x hours'
let v be the speed  of second car and V be speed of first car.
Then time taken by first car=x+2
V(x+2)=vx (distance covered is same.)
[tex] \frac{v}{V} = \frac{x+2}{x} subtract 1 from both sides \frac{v-V}{V} = \frac{2}{x} v-V= \frac{2V}{x} [/tex]


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