Answer:
x = 3 or x = 1
Step-by-step explanation:
[tex] {4x}^{2} - 16x + 12 = 0 \\ {4x}^{2} - 4x - 12x + 12 = 0 \\ 4x(x - 1) - 12(x - 1) = 0 \\ (4x - 12)(x - 1) = 0 \\ [/tex]
(4x - 12) = 0 or (x - 1) = 0
[tex](4x - 12) = 0 \\ 4x - 12 = 0 \\ 4x = 0 + 12 \\ 4x = 12 \\x = \frac{12}{4} \\ x = 3 \\ [/tex]
[tex](x - 1) = 0 \\ x - 1 = 0 \\ x = 0 + 1 \\ x = 1[/tex]
x = 3 or x = 1 should be.
