Solubility product shows the extent to which the solid dissociates in solution. The solubility product of AgCl from the data provided is 1.56 x 10^-10.
The equation of the dissolution of silver chloride in water is shown below;
AgCl(aq) ⇄ Ag^+(aq) + Cl^-(aq)
We are told that the concentration of [tex]Ag^+ = 1.25 x10^-5 M[/tex]
The Solubility product of AgCl is obtained from;
[tex]K = [ Ag^+] [ Cl^-]\\Since [Ag^+] = [ Cl^-] = 1.25 x10^-5 M\\K = [1.25x10^-5]^2\\K =1.56 x 10^-10[/tex]
Missing parts;
A saturated AgCl solution was analyzed and found to contain 1.25 x 10^-5 M Ag+ ions. Use this value to calculate the solubility product of AgCl.
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