Answer:
[tex]\frac{x^{2} }{9} +\frac{y^{2} }{25} =1[/tex]
Step-by-step explanation:
a vertex at (0,-5), a co-vertex at (-3,0): major axis parallel to y axis
[tex]\frac{x^{2} }{b^{2} } +\frac{y^{2}}{a^{2} } =1\\\frac{x^{2} }{(-3)^{2} } +\frac{y^{2}}{(-5)^{2} } =1\\\\\frac{x^{2} }{9 } +\frac{y^{2}}{25 } =1\\[/tex]
