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Mr. brown drove from his home to his school at the rate of 25 mph and returned by a different route at the rate of 30 mph. the route by which he returned was 5 miles longer than the route by which he went. the return trip took 10 minutes less than the trip out. find the distance mr. brown traveled each way.

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MissPhiladelphia
If we let
x and t1 as the distance traveled and the travel time, respectively using the first route
y and t2 as the distance traveled and the travel time, respectively using the second route

Then we have the equations:
x = 25 t1
y = 30 t2
y = x + 5
t2 = t1 - 10/60

Solving of x, y, t1 and t2
x = 50 mi
y = 55 mi
t1 = 2 hr
t2 = 1.83 hr
SenpaiTrill
Hello there.

Mr. brown drove from his home to his school at the rate of 25 mph and returned by a different route at the rate of 30 mph. the route by which he returned was 5 miles longer than the route by which he went. the return trip took 10 minutes less than the trip out. find the distance mr. brown traveled each way.

 1.83 hr

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