A calorimeter contains 500 g of water at 25°C. You place a hand warmer containing 100 g of liquid sodium acetate (NaAC) inside the calorimeter. When the sodium acetate finishes crystallizing, the temperature of the water inside the calorimeter is 32.2°C. The specific heat of water is
4.18 J/g-°C. What is the enthalpy of fusion (ΔHf) of the sodium acetate? Show your work.

Respuesta :

The heat absorbed by the water is
Q = 500 (4.18) (32.2 - 25)
Q = 15048 J

The enthalpy of fusion of the sodium acetate is:
ΔHf = Q / m
ΔHf = 15048 / 100
ΔHf = 150.48 J/g

Answer:The enthalpy of fusion [tex](ΔH_f)[/tex] of the sodium acetate is 12.344 kJ/mol.

Explanation:

Heat absorbed by the water: Q

Change in temperature of water,[tex]\Delta T=32.2^oC-25^oC=7.2^oC[/tex]

Specific heat of water = 4.18 J/g°C

Mass of water = m= 500 g

[tex]Q=500 g\times 4.18 J/g ^oC\times 7.2^oC=15,048 J[/tex]

[tex]\Delta H_f[/tex] is the heat energy required to melt the one mole of substance.

When 200 g of sodium acetate crystallizes it gave 15,048 Joules of heat which was absorbed by the water in calorimeter.

[tex]NaAC(l)\rightarrow NaAC(s),\Delta H_f=?[/tex]

Moles of NaAC=[tex]\frac{100 g}{82.03 g.mol}=1.2190 mol[/tex]

[tex]\Delta H_f=\frac{15,048 J}{1.2190 mol}=12,344 J/mol=12.344 kJ/mol[/tex]

The enthalpy of fusion [tex](ΔH_f)[/tex] of the sodium acetate is 12.344 kJ/mol.