Isaiah claims that B'C'D' is a dilation of BCD using A
as the center of dilation.
Convince Isaiah that his claim is not true.

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MrRoyal MrRoyal · Answer 1 · 2021-10-09T06:25:20+02:00

Dilation involves changing the size of a figure.

Isaiah's claim is not true because the [tex]\mathbf{\angle BCD}[/tex] is larger than [tex]\mathbf{\angle B'C'D'}[/tex]

Dilation is not a rigid transformation, however it does not change the angles of the figures it dilates.

The above statement implies that,

The measure of [tex]\mathbf{\angle BCD}[/tex] and [tex]\mathbf{\angle B'C'D'}[/tex] should be the same

However, we can see that;

[tex]\mathbf{\angle BCD}[/tex] and [tex]\mathbf{\angle B'C'D'}[/tex] are not equal.

In fact,

[tex]\mathbf{\angle BCD}[/tex] is larger than [tex]\mathbf{\angle B'C'D'}[/tex]

Hence, Isaiah's claim is not true