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What is the equation of a line that is parallel to the line 2x 5y = 10 and passes through the point (–5, 1)? Check all that apply. y = −Two-fifthsx − 1 2x 5y = −5 y = −Two-fifthsx − 3 2x 5y = −15 y − 1= −Two-fifths(x 5)

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The equation of the line parallel to the line 2x 5y = 10 and passes through the point (–5, 1) is y = (-2/5)x - 1

The standard form of a linear equation is given by:

y = mx + b

Where y is a dependent variable, x is an independent variable, m is the slope of the line (the rate of change), b is the y intercept (that is the initial value of y).

Given that the line is parallel to 2x + 5y = 10.

2x + 5y = 10

5y = -2x + 10

y = (-2/5)x + 2

Therefore the slope of the line 2x + 5y = 10 is -2/5

If two lines are parallel to each other, they have the same slope. Hence:

Slope of the line parallel to 2x + 5y = 10 is -2/5. This line also passes through point (-5, 1). The equation of this line is:

[tex]y-y_1=m(x-x_1)\\\\y-1=\frac{-2}{5} (x-(-5))\\\\y-1=\frac{-2}{5} (x+5)\\\\y=\frac{-2}{5} x-1[/tex]

The line has an equation of y = (-2/5)x - 1

Find out more at: https://brainly.com/question/18140287

G0ZZ

Answer:

y − 1= −Two-fifths(x + 5) ||  2x + 5y = −5   ||   y = −Two-fifthsx − 1

Explanation:

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