The tiger's position at time t is given by
x (horizontal) = (4.5 m/s) t
y (vertical) = 7.5 m - 1/2 gt ²
Solve y = 0 for t to find the time it takes for the tiger to reach the ground :
0 = 7.5 m - 1/2 (9.8 m/s²) t ²
===> t = √(2 (7.5 m) / (9.8 m/s²)) ≈ 1.2 s
Evaluate x at this time :
x = (4.5 m/s) (1.2 s) ≈ 5.6 m
