We have that the change after 2 minutes and its final speed be
v_2-v_1=0.624m/s
v_2=-0.136
From the question we are told
Suppose that a conveyor belt has an average acceleration of 0.0052m/s^2.
• How much does it change after 2 minutes?
• If the initial speed is 0.76m/s, what will its final speed be?
Generally the equation for the average acceleration a is mathematically given as
a)
[tex]a = {v_2-v_1}{t}\\\\0.0052 = {v_2-v_1}{2*60}\\\\v_2-v_1=0.0052 *2*60\\\\[/tex]
v_2-v_1=0.624m/s
b)
Since
[tex]v_2-v_1=0.624m/s\\\\v_2=0.624-0.76[/tex]
v_2=-0.136
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