I tried solving for K, but I got kinda confused. Can anyone help me out here?

Answer:
k = [tex]\frac{3}{5}\\[/tex]
Step-by-step explanation:
Assuming the question number is 27 and the equation is:
[tex]80 = 10 * 32^k[/tex]
80 = 10( [tex]32^k[/tex] )
Firstly, we can isolate the [tex]32^k[/tex] by dividing both sides of the equation by 10:
[tex]\frac{80}{10} = \frac{10(32^k)}{10}[/tex]
8 = [tex]32^k[/tex]
Now, we can find the unknown exponent using logarithms:
[tex]log(8) = k * log(32)[/tex]
Rearrange to make the subject k:
[tex]k = \frac{log8}{log32}[/tex]
k = [tex]\frac{3}{5}\\[/tex]
Hope this helps!