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A small sphere of mass 0.5g is suspended by a string 50cm long, with the string kept taut, the ball is whirled in a horizontal circle of radius 25cm. calculate its angular speed in radians per second

Respuesta :

Answer:

Explanation:

The angle the string makes with the vertical is

θ = arcsin(25/50) = 30°

The vertical component of the string tension must support the weight of the sphere. The horizontal component must supply the needed centripetal force

tanθ = mω²R / mg = ω²R/g

ω = √(gtanθ/R) = √(9.8tan30/0.25)

ω = 4.7573... = 4.8 rad/s

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