The speed of the car in terms of the average velocity is [tex]\frac{v(a+ b) }{\sqrt{a^2 + b^2} }[/tex]
The given parameters;
The average velocity of the car is defined as the rate of change of displacement.
[tex]average \ velocity = \frac{displacement}{time}[/tex]
The displacement of the car along the rectangle is obtained by applying Pythagoras theorem to calculate the diagonal of the rectangle ;
c² = a² + b²
[tex]c = \sqrt{a^2 + b^2}[/tex]
[tex]v= \frac{\sqrt{a^2 + b^2} }{t} \\\\t = \frac{\sqrt{a^2 + b^2} }{v}[/tex]
The speed of the car is defined as the rate of change of distance.
[tex]speed = \frac{distance}{time}[/tex]
The distance around the 2 sides of the rectangle is calculated as;
Distance = a + b
[tex]speed = \frac{a+b}{t}[/tex]
[tex]speed = \frac{v(a+ b)}{\sqrt{a^2 + b^2} }[/tex]
Thus, the speed of the car is [tex]\frac{v(a+ b) }{\sqrt{a^2 + b^2} }[/tex]
Learn more here: https://brainly.com/question/17345815
