need help please with this problem

The surface area of the pyramid, in square feet is [tex]84.84[/tex] [tex]ft^2[/tex]
All the triangles are equilateral.
Here, the side of one triangle is perfectly in line with the side of the other triangle as seen in the net.
So, all the triangles are congruent and hence the area of all the triangles will also be equal.
Base of the triangle [tex]= 7[/tex] ft.
Height of the triangle [tex]= 6.06[/tex] ft
Area [tex]= \frac{1}{2} \times base \times height[/tex]
Area [tex]= \frac{1}{2} \times 7 \times 6.06[/tex]
Area [tex]= 21.21 ft^2[/tex]
There are [tex]4[/tex] triangles in the net.
So, total area [tex]= 4 \times 21.21[/tex]
[tex]= 84.84 ft^2[/tex]
Learn more about area here:
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