a 1.50*10^-5 C charge feels a 2.89*10^-3 N force when it moves 288m/s perpendicular (90) deg to a magnetic field. how strong is the field?

Respuesta :

6.68, -1
Explanation: correct for acellus

The strength of the field will be = B= 0.669 T

What is force in a magnetic field ?

Force in a magnetic field is an attraction or repulsion that arises between electrically charged particles because of their motion or it is a consequence of electromagnetic force and is caused due to motion .

Force in a magnetic field  on a charge can be calculated by

F = q*v*B sin (theta ) =  2.89*10^-3 N

q = charge experiencing force  =  1.50*10^-5 C

v = velocity of charge = 288m/s

B= magnetic field = ?

theta = angle between speed of charge and magnetic field = 90 degree

Force in a magnetic field (F) = q*v*B sin (theta )

2.89*10^-3 N = 1.50*10^-5 C * 288m/s * B * sin 90° (sin 90° = 1)

B = 2.89 * 10 ^ -3 / 1.50 * 10^-5 * 288

B= 0.669 T

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