Respuesta :
The kinematics allows to find the answers to this exercise of vertical launching are;
- Initial velocity is 4.60 m / s
- Time to maximum height t = 0.474 s
- The time to return to the starting point t = 0.947 s
The vertical launch is a part of the kinematics that analyzes the vertical movement of the body, in this case the acceleration of the system is the acceleration of gravity (g = 9.8 m / s²).
let's set a frame of reference where the upward direction is taken as positive
v² = v₀² - 2 g y
Where v and v₀ are the current and initial velocities, respectively, g the acceleration e and the height
In this case, when the body reaches the highest part, its velocity is zero.
0 = vo² - 2 gy
v₀ = [tex]\sqrt{2gy}[/tex]
v₀ = [tex]\sqrt{2 \ 9.8 \ 1.10}[/tex]
v₀ = 4.64 m / s
The time it takes to get to this point is
v = v₀ - g t
0 = v₀ -gt
t = [tex]\frac{v_o}{g}[/tex]
t = [tex]\frac{4.64}{9.8}[/tex]
t = 0.474 s
The time it takes for the entire movement can be calculated with
y = v₀ t - ½ g t²
When it reaches the ground its height is zero
0 = 4.64 t - ½ 9.8 t²
0 = t (4.64 - 4.9 t)
The solutions of this equation are
t = 0 s
This time corresponds to the moment of leaving the body
t = 4.64 / 4.9
t = 0.947 s
In conclusion using kinematics we can find the answers are;
- Initial velocity is 4.60 m / s
- Time to maximum height t = 0.474 s
- The time to return to the starting point t = 0.947 s
Learn more about vertical launch here:
https://brainly.com/question/18820774
