The magnitude of the acceleration of the cart is 26.25.
Given:
Student releases cart from the top of a ramp that travels 210 cm before hitting stooper.
A cart reaches the bottom in 4.00 seconds.
To find:
The magnitude of the acceleration of the cart
Solution:
The distance travelled by the cart = s = 210 cm
The time taken by cart to reach bottom= t = 4.00 s
The initial velocity of the cart = u = 0 cm/s
Using second equation motion:
[tex]s=ut+\frac{1}{2}at^2\\\\210 cm= 0\times 4.00 s+\frac{1}{2}a(4.00s)^2\\\\210 cm=\frac{1}{2}a(4.00s)^2\\\\a=\frac{2\times 210 cm}{(4.00s)^2}=26.25 cm/s^2[/tex]
The magnitude of the acceleration of the cart is 26.25.
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