[tex]\Huge\boxed{\frac{1}{2}\ \textsf{feet}\ \Large\textsf{(6 inches)}}[/tex]
To solve this question, we simply need to subtract the two numbers.
[tex]\displaystyle6\frac{5}{6}-6\frac{1}{3}[/tex]
We'll start by changing these into improper fractions to simplify things for now.
[tex]\displaystyle\begin{aligned}(\frac{36}{6}+\frac{5}{6})&-(\frac{18}{3}+\frac{1}{3})\\\frac{41}{6}&-\frac{19}{3}\end{aligned}[/tex]
Now, we need to make these fractions share a common denominator. We'll do this by multiplying the second fraction by [tex]2[/tex]. Keep in mind that whatever is done to the denominator must also be done to the numerator.
[tex]\displaystyle\frac{41}{6}-\frac{19\cdot2}{3\cdot2}\\\frac{41}{6}-\frac{38}{6}[/tex]
Finally, subtract the numerators and keep the denominators.
[tex]\displaystyle\frac{41-38}{6}\\\frac{3}{6}[/tex]
We can simplify this fraction by dividing both the numerator and the denominator by [tex]3[/tex].
[tex]\displaystyle\frac{3\div3}{6\div3}\\\large\boxed{\frac{1}{2}}[/tex]
