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There are two numbers whose $400^{\text{th}}$ powers are equal to $9^{1000}$. In other words, there are two numbers that can replace $\blacksquare$ in the equation
$\blacksquare^{400} = 9^{1000},$making the equation true.

Find the smaller of the two numbers.

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Person12327

Answer: ± 243

Work:

x^400 = 9^1000

so the GCF of 400, 1000  = 200

(x^2)^200 = (9^5)^200

(x^2) = 9^5      

(x^2) = (3^2)^2

x^2  = 3^10    

x = ± √[3^10]  =   ± [ 3] ^(10/2)  =  ± [3]^5  =  ± 243

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