Suppose that the height of a falling object t seconds after being dropped from a height of 275 feet is given by f(t) = 275 − 16t2 feet. Find the average velocity between times t = 3 and t = 4.

MATH

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Answer:

112 m/s

Step-by-step explanation:

height at t = 3

275 - 16(3²) = 131 ft

height at t = 4

275 - 16(4²) = 19 ft

Average vertical velocity for 3 ≤ t ≤ 4

v = d/t = (131 - 19) / (4 - 3) = 112 m/s