First, apply the cross multiplication method to each given. Then, do substitution if necessary.
[tex]7. \begin{gathered} \frac{2n}{3} = \frac{5}{2} \\ 4n = (3)(5) \\ 4n = 15 \\ \frac{ \cancel{4}n}{ \cancel{4}} = \frac{15}{4} \\ \sf \bold{n = 3.75}\end{gathered}[/tex]
[tex]8. \begin{gathered} \frac{6}{10} = \frac{3}{n} \\ 6n = (10)(3) \\ 6n = 30 \\ \frac{ \cancel{6}n}{ \cancel{6}} = \frac{30}{6} \\ \sf \bold{n = 5}\end{gathered}[/tex]
[tex]9. \begin{gathered} \frac{n}{7} = \frac{2}{5} \\ 5n = (7)(2) \\ 5n = 14 \\ \frac{ \cancel{5}n}{ \cancel{5}} = \frac{14}{5} \\ \sf \bold{n = 2.8}\end{gathered}[/tex]
[tex]10. \begin{gathered} \frac{3}{n} = \frac{5}{10} \\ 5n = (3)(10) \\ 5n = 30 \\ \frac{ \cancel{5}n}{ \cancel{5}} = \frac{30}{5} \\ \sf \bold{n = 6}\end{gathered}[/tex]
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