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Write the equation of the line that is perpendicular to y=3/4 x - 1 and
passes through the point (3,-3).

Respuesta :

Answer:

[tex]y = - \frac{4}{3}x + 1[/tex]

Step-by-step explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept.

y= ¾x -1

Slope= ¾

The product of the slopes of perpendicular lines is -1.

Let the slope of the line be m.

m(¾)= -1

m= -1 ÷¾

[tex]m = - \frac{4}{3} [/tex]

[tex]y = - \frac{4}{3} x + c[/tex]

To find the value of the y-intercept, substitute a pair of coordinates into the equation.

When x= 3, y= -3,

[tex] - 3 = - \frac{4}{3} (3) + c[/tex]

[tex] - 3 = - 4 + c[/tex]

c= 4 -3

c= 1

Thus, the equation of the line is [tex]y = - \frac{4}{3} x + 1[/tex].