Respuesta :
Suppose X∼N(16.5,0.5), and x=16. Find and interpret the z-score of the standardized normal random variable The z score when x=16.
What is a variabe?
A variable is something that varies in any data.
- X sim N(16.5.0.5)
- Therefore (mu, sigma ^ 2) = (16.five, 0.five) mu = sixteen.five sigma ^ 2 = 0.five sigma = sqrt(0.five) x = sixteen z-rating is given by z = (x - mu)/sigma = 16-16.5sqrt 0.five = -0.five sqrt 0.five=- sqrt 0.5.
The z-rating while X=sixteen is -1. The imply is 16.5. This z-rating tells you that X=sixteen is 1 well-known deviation to Left of the imply. The imply is 16.5.
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