Answer:
± 2
Step-by-step explanation:
let the number be n , then
n² - 4 = 0 ( add 4 to both sides )
n² = 4 ( take square root of both sides )
n = ± [tex]\sqrt{4}[/tex] = ± 2
The number is - 2 or 2
If ∈ℝ, prove that 0<<1 ⟹ 0<2< and >1⟹2>.
I found some solution for rational 's but I'm stuck with real 's.
