Answer:
[tex] {x}^{2} + {(x - 3)}^{2} = 5 \\ {x}^{2} + {x}^{2} - 6x + 9 = 5 \\ 2 {x}^{2} - 6x + 4 = 0) \div 2 \\ {x}^{2} - 3x + 2 = 0 \\ (x - 1)(x - 2) = 0 \\ x = 1 \: or \: x = 2 \\ for \: x = 1 \\ y = 1 - 3 = - 2 \\ for \: x = 2 \\ y = 2 - 3 = - 1[/tex]
