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the freefall acceleration on the moon is 1/6 of its value on earth. suppose he hit the ball with a speed of 25m/s an angle of 30 above the horizontal.

a. how long was the ball in flight?
b. how far did it travel?
c. How much farther would it travel on the moon than on earth?

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DALAU

Answer:

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Explanation:

a. time of flight =(2usinθ)/(g/6)

= 12usinθ/g

= (12x25xsin(30))/g

= 15.306 seconds

b. Range = u2sin(2θ)/(g/6)

= 6u2sin(2θ)/g

= (6x252xsin(60)) /9.8

= 331.387 metres

c. Range on earth = Range on moon/6 = 55.23 metres

On moon it travels 331.387 - 55.23 = 276.155 metres more than on earth

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